3(-4+-3x+x^2)=0

Solution for 3(-4+-3x+x^2)=0 equation:

3(-4+-3x+x^2)=0

We use the square of the difference formula

3(-4-3x+x^2)=0

We multiply parentheses

3x^2-9x-12=0

a = 3; b = -9; c = -12;
Δ = b2-4ac
Δ = -92-4·3·(-12)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-15}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+15}{2*3}=\frac{24}{6}
=4
$